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Given, tan-1 x + tan-1 (1/x)
= tan-1 [{x + (1/x)}/{1 - x * (1/x)}] {Apply tan-1 A + tan-1 B formula}
= tan-1 [{x + (1/x)}/(1 - 1)]
= tan-1 [{x + (1/x)}/0]
= tan-1 ∞
= π/2 {since tan-1 ∞ = π/2}
So, tan-1 x + tan-1 (1/x) = π/2